Sex Predator - Societal Protection vs. Constitutional Rights Essay

Sex Predator - Societal Protection vs. Constitutional Rights - Essay Example Individuals who engage in sex crimes such as rape or child sex are known as sexual predators. However, the term may be applied depending on the moral beliefs and sometimes may not be a criminal behaviour. In communities, a predator may refer to somebody who seeks dominance or submission in an exploitative manner. The Constitution and the society have different views regarding sexual predators and the legality of the action. The sexual predator law, the statute mandates long periods of civil commitment for habitual sexual offenders and sexual psychopaths in their criminal sentences. For instance, in the US sexual predator laws were very popular in the 1990s although they led to constitutional questions (Carpenter, 2012). One of the concerns was the double jeopardy and the need to balance the rights of the offenders and those of the community in which they came from. The laws' strictness is due to the possibility of a sex offender repeating an action once released from prison and there fore, long-term jail period is necessary. The offenders also undergo screening to rule out the possibility of a mental disorder to the offender and give treatment before passing judgment. The state has the role of detaining the offender and give treatment until the individual is cured of the illness as explained by Bartol & Bartol (2012). The supreme court of the United States holds the Kansa’s sexual predator law, which requires the state prove mental abnormality as a before detainment of the offender.

Math Portifolio Matrix binomials Problem Example | Topics and Well Written Essays - 750 words

Portifolio Matrix binomials - Math Problem Example Based on these computations, we derive the general expression for An: An = (2n-1)(an)(X) We must check for the validity of this equation by applying it to solve for A2 with a=3. A2 = 22-1321111 = 18181818 , same as the previous answer. Hence, the expression is valid. Now, take b=2; B = 2-2-22: B2 = 2-2-222-2-22 = 8-8-88 B3 = 2-2-222-2-222-2-22 = 8-8-882-2-22= 32-32-3232 B4 = 2-2-222-2-222-2-222-2-22 = 128-128-128128 Hence, we arrive at the general expression Bn = (2n-1)(bn)(Y). Note that the procedure we used is consistent with that used for matrix A, even up to the checking for validity. For the final task, we are given a new matrix M = a+ba-ba-ba+b. We must show that M = A + B and M2 = A2 + B2 using the algebraic method. Again, define A and B: A=a1111=aaaa B=b1-1-11=b-b-bb A+B= aaaa+b-b-bb=a+ba-ba-ba+b M= a+ba-ba-ba+b M=A+B equation 1 We have proven the first relationship to be true. Now we must proceed to showing M2 = A2 + B2. From equation 1, M = A + B, therefore, by substitution, this is the same as saying M2 = (A + B)2. Previously we have shown that and expression of this form X+Yn= Xn+ Yn. Hence: M2=a+ba-ba-ba+ba+ba-ba-ba+b M2=a+ba+ba-ba-ba-ba+ba-ba+ba-ba+ba-ba+ba-ba-ba+ba+b M2=2a2+2b22a2-2b22a2-2b22a2+2b2 A2=2a22a22a22a2 and B2=2b2-2b2-2b2-2b2 A2+ B2=2a2+2b22a2-2b22a2-2b22a2+2b2 M2 = A2 + B2 equation 2 Recall that A = aX and B = bY. We now produce a general statement for Mn in terms of aX and bY: Mn = An + Bn or by substitution, Mn= (aX)n + (bY)n furthermore, Mn = anXn + bnYn Verifying this equation, we try using a=2, b=3, and n=2: A=2222 and B=3-3-33 If we use, (A+B)2=5-1-155-1-15=25+1-5-5-5-525+1=26-10-1026 Now, using the general statement: M2=22X2+ 32Y2=222222222222+232-232-232232=8+188-188-188+18... Also given were matrices A and B, defined as aX and bY, respectively. Note that a and b are constants. First, recall that when multiplying constants to any matrix, we simply multiply the constant with every element of the matrix. To illustrate: Once again, the general expression is shown valid. It is also important to note that this general statement will only yield results for values of n>0. Matrices can not be raised to negative exponents.